4x^2+42=2x-8

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Solution for 4x^2+42=2x-8 equation: 



4x^2+42=2x-8

We move all terms to the left:

4x^2+42-(2x-8)=0

We get rid of parentheses

4x^2-2x+8+42=0

We add all the numbers together, and all the variables

4x^2-2x+50=0

a = 4; b = -2; c = +50;
Δ = b2-4ac
Δ = -22-4·4·50
Δ = -796
Delta is less than zero, so there is no solution for the equation

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